un proyectil se dispara con una velocidad inicial de 450 pies/ seg y con un angulo de elevacion de 30° sobre la horizontal, calcular a) su posición y velocidad despues de 8s,b) la altura máxima

Accepted Solution


A projectile is fired with an initial velocity of 450 ft / sec and with an elevation angle of 30 ° above the horizontal, calculate a) its position and speed after 8s,
The position after 8 seconds will be as follows
horizontal distance:
=3600 ft

 b) the maximum height reached will be given by:
H=[v² sin²θ]/2g
Plugging in the values we get:
H=2,531.25 ft