Q:

In mathematics, the Nth harmonic number is defined to be 1 + 1/2 + 1/3 + 1/4 + ... + 1/N. So, the first harmonic number is 1, the second is 1.5, the third is 1.83333... and so on. Assume that n is an integer variable whose value is some positive integer N. Assume also that cl is a variable whose value is the Nth harmonic number. Write an expression whose value is the (N+1)th harmonic number.

Accepted Solution

A:
Answer:cl   +   1/(N+1)Step-by-step explanation:If we assume that the Nth harmonic number is cl. Then we are assuming that 1+1/2+1/3+1/4+...+1/N=clAnd we know that the (N+1)th harmonic number can be found by doing1+1/2+1/3+1/4+...+1/N+1/(N+1)=cl    +   1/(N+1)The (N+1)th harmonic number is cl   +   1/(N+1) given that the Nth term is clOther way to see the answers: Maybe you want to write it as a single fraction so you have[cl(N+1)+1]/(N+1)=[cl*N+cl+1]/(N+1)